Metamath Proof Explorer


Theorem rereccld

Description: Closure law for reciprocal. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses redivcld.1 ⊢ φ → A ∈ ℝ
rereccld.2 ⊢ φ → A ≠ 0
Assertion rereccld ⊢ φ → 1 A ∈ ℝ

Proof

Step Hyp Ref Expression
1 redivcld.1 ⊢ φ → A ∈ ℝ
2 rereccld.2 ⊢ φ → A ≠ 0
3 rereccl ⊢ A ∈ ℝ ∧ A ≠ 0 → 1 A ∈ ℝ
4 1 2 3 syl2anc ⊢ φ → 1 A ∈ ℝ