Metamath Proof Explorer


Theorem divsassd

Description: An associative law for surreal division. (Contributed by Scott Fenton, 16-Mar-2025)

Ref Expression
Hypotheses divsassd.1 ⊢ φ → A ∈ No
divsassd.2 ⊢ φ → B ∈ No
divsassd.3 ⊢ φ → C ∈ No
divsassd.4 ⊢ φ → C ≠ 0 s
Assertion divsassd ⊢ φ → A ⋅ s B / su C = A ⋅ s B / su C

Proof

Step Hyp Ref Expression
1 divsassd.1 ⊢ φ → A ∈ No
2 divsassd.2 ⊢ φ → B ∈ No
3 divsassd.3 ⊢ φ → C ∈ No
4 divsassd.4 ⊢ φ → C ≠ 0 s
5 3 4 recsexd ⊢ φ → ∃ x ∈ No C ⋅ s x = 1 s
6 1 2 3 4 5 divsasswd ⊢ φ → A ⋅ s B / su C = A ⋅ s B / su C