Metamath Proof Explorer


Theorem divscan1wd

Description: A weak cancellation law for surreal division. (Contributed by Scott Fenton, 13-Mar-2025)

Ref Expression
Hypotheses divscan2wd.1 ⊢ φ → A ∈ No
divscan2wd.2 ⊢ φ → B ∈ No
divscan2wd.3 ⊢ φ → B ≠ 0 s
divscan2wd.4 ⊢ φ → ∃ x ∈ No B ⋅ s x = 1 s
Assertion divscan1wd ⊢ φ → A / su B ⋅ s B = A

Proof

Step Hyp Ref Expression
1 divscan2wd.1 ⊢ φ → A ∈ No
2 divscan2wd.2 ⊢ φ → B ∈ No
3 divscan2wd.3 ⊢ φ → B ≠ 0 s
4 divscan2wd.4 ⊢ φ → ∃ x ∈ No B ⋅ s x = 1 s
5 1 2 3 4 divsclwd ⊢ φ → A / su B ∈ No
6 5 2 mulscomd ⊢ φ → A / su B ⋅ s B = B ⋅ s A / su B
7 1 2 3 4 divscan2wd ⊢ φ → B ⋅ s A / su B = A
8 6 7 eqtrd ⊢ φ → A / su B ⋅ s B = A