Metamath Proof Explorer


Theorem divsclwd

Description: Weak division closure law. (Contributed by Scott Fenton, 12-Mar-2025)

Ref Expression
Hypotheses divsclwd.1 ⊢ φ → A ∈ No
divsclwd.2 ⊢ φ → B ∈ No
divsclwd.3 ⊢ φ → B ≠ 0 s
divsclwd.4 ⊢ φ → ∃ x ∈ No B ⋅ s x = 1 s
Assertion divsclwd ⊢ φ → A / su B ∈ No

Proof

Step Hyp Ref Expression
1 divsclwd.1 ⊢ φ → A ∈ No
2 divsclwd.2 ⊢ φ → B ∈ No
3 divsclwd.3 ⊢ φ → B ≠ 0 s
4 divsclwd.4 ⊢ φ → ∃ x ∈ No B ⋅ s x = 1 s
5 divsclw ⊢ A ∈ No ∧ B ∈ No ∧ B ≠ 0 s ∧ ∃ x ∈ No B ⋅ s x = 1 s → A / su B ∈ No
6 1 2 3 4 5 syl31anc ⊢ φ → A / su B ∈ No