Metamath Proof Explorer


Theorem dmmpog

Description: Domain of an operation given by the maps-to notation, closed form of dmmpo . Caution: This theorem is only valid in the very special case where the value of the mapping is a constant! (Contributed by Alexander van der Vekens, 1-Jun-2017) (Proof shortened by AV, 10-Feb-2019)

Ref Expression
Hypothesis dmmpog.f ⊢ F = x ∈ A , y ∈ B ⟼ C
Assertion dmmpog ⊢ C ∈ V → dom ⁡ F = A × B

Proof

Step Hyp Ref Expression
1 dmmpog.f ⊢ F = x ∈ A , y ∈ B ⟼ C
2 simpl ⊢ C ∈ V ∧ x ∈ A ∧ y ∈ B → C ∈ V
3 2 ralrimivva ⊢ C ∈ V → ∀ x ∈ A ∀ y ∈ B C ∈ V
4 1 dmmpoga ⊢ ∀ x ∈ A ∀ y ∈ B C ∈ V → dom ⁡ F = A × B
5 3 4 syl ⊢ C ∈ V → dom ⁡ F = A × B