Metamath Proof Explorer


Theorem dmmpog

Description: Domain of an operation given by the maps-to notation, closed form of dmmpo . Caution: This theorem is only valid in the very special case where the value of the mapping is a constant! (Contributed by Alexander van der Vekens, 1-Jun-2017) (Proof shortened by AV, 10-Feb-2019)

Ref Expression
Hypothesis dmmpog.f ⊢ 𝐹 = ( 𝑥 ∈ 𝐴 , 𝑦 ∈ 𝐵 ↦ 𝐶 )
Assertion dmmpog ( 𝐶 ∈ 𝑉 → dom 𝐹 = ( 𝐴 × 𝐵 ) )

Proof

Step Hyp Ref Expression
1 dmmpog.f ⊢ 𝐹 = ( 𝑥 ∈ 𝐴 , 𝑦 ∈ 𝐵 ↦ 𝐶 )
2 simpl ⊢ ( ( 𝐶 ∈ 𝑉 ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵 ) ) → 𝐶 ∈ 𝑉 )
3 2 ralrimivva ⊢ ( 𝐶 ∈ 𝑉 → ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ 𝐵 𝐶 ∈ 𝑉 )
4 1 dmmpoga ⊢ ( ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ 𝐵 𝐶 ∈ 𝑉 → dom 𝐹 = ( 𝐴 × 𝐵 ) )
5 3 4 syl ⊢ ( 𝐶 ∈ 𝑉 → dom 𝐹 = ( 𝐴 × 𝐵 ) )