Metamath Proof Explorer


Theorem dmqseqeq1d

Description: Equality theorem for domain quotient set, deduction version. (Contributed by Peter Mazsa, 26-Sep-2021)

Ref Expression
Hypothesis dmqseqeq1d.1 ⊢ φ → R = S
Assertion dmqseqeq1d ⊢ φ → dom ⁡ R / R = A ↔ dom ⁡ S / S = A

Proof

Step Hyp Ref Expression
1 dmqseqeq1d.1 ⊢ φ → R = S
2 dmqseqeq1 ⊢ R = S → dom ⁡ R / R = A ↔ dom ⁡ S / S = A
3 1 2 syl ⊢ φ → dom ⁡ R / R = A ↔ dom ⁡ S / S = A