Metamath Proof Explorer


Theorem dmqseqeq1i

Description: Equality theorem for domain quotient, inference version. (Contributed by Peter Mazsa, 26-Sep-2021)

Ref Expression
Hypothesis dmqseqeq1i.1 ⊢ R = S
Assertion dmqseqeq1i ⊢ dom ⁡ R / R = A ↔ dom ⁡ S / S = A

Proof

Step Hyp Ref Expression
1 dmqseqeq1i.1 ⊢ R = S
2 dmqseqeq1 ⊢ R = S → dom ⁡ R / R = A ↔ dom ⁡ S / S = A
3 1 2 ax-mp ⊢ dom ⁡ R / R = A ↔ dom ⁡ S / S = A