Metamath Proof Explorer


Theorem dvrfval

Description: Division operation in a ring. (Contributed by Mario Carneiro, 2-Jul-2014) (Revised by Mario Carneiro, 2-Dec-2014) (Proof shortened by AV, 2-Mar-2024)

Ref Expression
Hypotheses dvrval.b ⊢ B = Base R
dvrval.t ⊢ · ˙ = ⋅ R
dvrval.u ⊢ U = Unit ⁡ R
dvrval.i ⊢ I = inv r ⁡ R
dvrval.d ⊢ × ˙ = / r ⁡ R
Assertion dvrfval ⊢ × ˙ = x ∈ B , y ∈ U ⟼ x · ˙ I ⁡ y

Proof

Step Hyp Ref Expression
1 dvrval.b ⊢ B = Base R
2 dvrval.t ⊢ · ˙ = ⋅ R
3 dvrval.u ⊢ U = Unit ⁡ R
4 dvrval.i ⊢ I = inv r ⁡ R
5 dvrval.d ⊢ × ˙ = / r ⁡ R
6 fveq2 ⊢ r = R → Base r = Base R
7 6 1 eqtr4di ⊢ r = R → Base r = B
8 fveq2 ⊢ r = R → Unit ⁡ r = Unit ⁡ R
9 8 3 eqtr4di ⊢ r = R → Unit ⁡ r = U
10 fveq2 ⊢ r = R → ⋅ r = ⋅ R
11 10 2 eqtr4di ⊢ r = R → ⋅ r = · ˙
12 eqidd ⊢ r = R → x = x
13 fveq2 ⊢ r = R → inv r ⁡ r = inv r ⁡ R
14 13 4 eqtr4di ⊢ r = R → inv r ⁡ r = I
15 14 fveq1d ⊢ r = R → inv r ⁡ r ⁡ y = I ⁡ y
16 11 12 15 oveq123d ⊢ r = R → x ⋅ r inv r ⁡ r ⁡ y = x · ˙ I ⁡ y
17 7 9 16 mpoeq123dv ⊢ r = R → x ∈ Base r , y ∈ Unit ⁡ r ⟼ x ⋅ r inv r ⁡ r ⁡ y = x ∈ B , y ∈ U ⟼ x · ˙ I ⁡ y
18 df-dvr ⊢ / r = r ∈ V ⟼ x ∈ Base r , y ∈ Unit ⁡ r ⟼ x ⋅ r inv r ⁡ r ⁡ y
19 1 fvexi ⊢ B ∈ V
20 3 fvexi ⊢ U ∈ V
21 19 20 mpoex ⊢ x ∈ B , y ∈ U ⟼ x · ˙ I ⁡ y ∈ V
22 17 18 21 fvmpt ⊢ R ∈ V → / r ⁡ R = x ∈ B , y ∈ U ⟼ x · ˙ I ⁡ y
23 fvprc ⊢ ¬ R ∈ V → / r ⁡ R = ∅
24 fvprc ⊢ ¬ R ∈ V → Base R = ∅
25 1 24 eqtrid ⊢ ¬ R ∈ V → B = ∅
26 25 orcd ⊢ ¬ R ∈ V → B = ∅ ∨ U = ∅
27 0mpo0 ⊢ B = ∅ ∨ U = ∅ → x ∈ B , y ∈ U ⟼ x · ˙ I ⁡ y = ∅
28 26 27 syl ⊢ ¬ R ∈ V → x ∈ B , y ∈ U ⟼ x · ˙ I ⁡ y = ∅
29 23 28 eqtr4d ⊢ ¬ R ∈ V → / r ⁡ R = x ∈ B , y ∈ U ⟼ x · ˙ I ⁡ y
30 22 29 pm2.61i ⊢ / r ⁡ R = x ∈ B , y ∈ U ⟼ x · ˙ I ⁡ y
31 5 30 eqtri ⊢ × ˙ = x ∈ B , y ∈ U ⟼ x · ˙ I ⁡ y