Metamath Proof Explorer


Theorem e2bir

Description: Right biconditional form of e2 . syl6ibr is e2bir without virtual deductions. (Contributed by Alan Sare, 29-Apr-2011) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypotheses e2bir.1 φ , ψ χ
e2bir.2 θ χ
Assertion e2bir φ , ψ θ

Proof

Step Hyp Ref Expression
1 e2bir.1 φ , ψ χ
2 e2bir.2 θ χ
3 2 biimpri χ θ
4 1 3 e2 φ , ψ θ