Metamath Proof Explorer


Theorem ecref

Description: All elements are in their own equivalence class. (Contributed by Thierry Arnoux, 14-Feb-2025)

Ref Expression
Assertion ecref ⊢ R Er X ∧ A ∈ X → A ∈ A R

Proof

Step Hyp Ref Expression
1 simpl ⊢ R Er X ∧ A ∈ X → R Er X
2 simpr ⊢ R Er X ∧ A ∈ X → A ∈ X
3 1 2 erref ⊢ R Er X ∧ A ∈ X → A R A
4 elecg ⊢ A ∈ X ∧ A ∈ X → A ∈ A R ↔ A R A
5 2 4 sylancom ⊢ R Er X ∧ A ∈ X → A ∈ A R ↔ A R A
6 3 5 mpbird ⊢ R Er X ∧ A ∈ X → A ∈ A R