Metamath Proof Explorer


Theorem efmnd1bas

Description: The monoid of endofunctions on a singleton consists of the identity only. (Contributed by AV, 31-Jan-2024)

Ref Expression
Hypotheses efmnd1bas.1 ⊢ G = EndoFMnd ⁡ A
efmnd1bas.2 ⊢ B = Base G
efmnd1bas.0 ⊢ A = I
Assertion efmnd1bas ⊢ I ∈ V → B = I I

Proof

Step Hyp Ref Expression
1 efmnd1bas.1 ⊢ G = EndoFMnd ⁡ A
2 efmnd1bas.2 ⊢ B = Base G
3 efmnd1bas.0 ⊢ A = I
4 3 fveq2i ⊢ EndoFMnd ⁡ A = EndoFMnd ⁡ I
5 1 4 eqtri ⊢ G = EndoFMnd ⁡ I
6 5 2 efmndbas ⊢ B = I I
7 fsng ⊢ I ∈ V ∧ I ∈ V → p : I ⟶ I ↔ p = I I
8 7 anidms ⊢ I ∈ V → p : I ⟶ I ↔ p = I I
9 snex ⊢ I ∈ V
10 9 9 elmap ⊢ p ∈ I I ↔ p : I ⟶ I
11 velsn ⊢ p ∈ I I ↔ p = I I
12 8 10 11 3bitr4g ⊢ I ∈ V → p ∈ I I ↔ p ∈ I I
13 12 eqrdv ⊢ I ∈ V → I I = I I
14 6 13 eqtrid ⊢ I ∈ V → B = I I