Metamath Proof Explorer


Theorem el

Description: Any set is an element of some other set. See elALT for a shorter proof using more axioms, and see elALT2 for a proof that uses ax-9 and ax-pow instead of ax-pr . (Contributed by NM, 4-Jan-2002) (Proof shortened by Andrew Salmon, 25-Jul-2011) Use ax-pr instead of ax-9 and ax-pow . (Revised by BTernaryTau, 2-Dec-2024) (Proof shortened by Matthew House, 6-Apr-2026)

Ref Expression
Assertion el ⊢ ∃ y x ∈ y

Proof

Step Hyp Ref Expression
1 ax-pr ⊢ ∃ y ∀ z z = x ∨ z = x → z ∈ y
2 orc ⊢ z = x → z = x ∨ z = x
3 ax8v1 ⊢ z = x → z ∈ y → x ∈ y
4 2 3 embantd ⊢ z = x → z = x ∨ z = x → z ∈ y → x ∈ y
5 4 spimvw ⊢ ∀ z z = x ∨ z = x → z ∈ y → x ∈ y
6 1 5 eximii ⊢ ∃ y x ∈ y