Metamath Proof Explorer


Theorem elab2gw

Description: Membership in a class abstraction, using two substitution hypotheses to avoid a disjoint variable condition on x and A , which is not usually significant since B is usually a constant. (Contributed by SN, 16-May-2024)

Ref Expression
Hypotheses elabgw.1 ⊢ x = y → φ ↔ ψ
elabgw.2 ⊢ y = A → ψ ↔ χ
elab2gw.3 ⊢ B = x | φ
Assertion elab2gw ⊢ A ∈ V → A ∈ B ↔ χ

Proof

Step Hyp Ref Expression
1 elabgw.1 ⊢ x = y → φ ↔ ψ
2 elabgw.2 ⊢ y = A → ψ ↔ χ
3 elab2gw.3 ⊢ B = x | φ
4 3 eleq2i ⊢ A ∈ B ↔ A ∈ x | φ
5 1 2 elabgw ⊢ A ∈ V → A ∈ x | φ ↔ χ
6 4 5 bitrid ⊢ A ∈ V → A ∈ B ↔ χ