Metamath Proof Explorer


Theorem elabd3

Description: Membership in a class abstraction, using implicit substitution. Deduction version of elab . (Contributed by GG, 12-Oct-2024)

Ref Expression
Hypotheses elabd3.ex ⊢ φ → A ∈ V
elabd3.is ⊢ φ ∧ x = A → ψ ↔ χ
Assertion elabd3 ⊢ φ → A ∈ x | ψ ↔ χ

Proof

Step Hyp Ref Expression
1 elabd3.ex ⊢ φ → A ∈ V
2 elabd3.is ⊢ φ ∧ x = A → ψ ↔ χ
3 eqidd ⊢ φ → x | ψ = x | ψ
4 1 3 2 elabd2 ⊢ φ → A ∈ x | ψ ↔ χ