Metamath Proof Explorer
		
		
		
		Description:  Membership in a class abstraction, using implicit substitution.
       Deduction version of elab .  (Contributed by GG, 12-Oct-2024)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | elabd3.ex |  | 
					
						|  |  | elabd3.is |  | 
				
					|  | Assertion | elabd3 |  | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | elabd3.ex |  | 
						
							| 2 |  | elabd3.is |  | 
						
							| 3 |  | eqidd |  | 
						
							| 4 | 1 3 2 | elabd2 |  |