Metamath Proof Explorer


Theorem elcnvintab

Description: Two ways of saying a set is an element of the converse of the intersection of a class. (Contributed by RP, 19-Aug-2020)

Ref Expression
Assertion elcnvintab ⊢ A ∈ ⋂ x | φ -1 ↔ A ∈ V × V ∧ ∀ x φ → A ∈ x -1

Proof

Step Hyp Ref Expression
1 eqid ⊢ y ∈ V × V ⟼ 2 nd ⁡ y 1 st ⁡ y = y ∈ V × V ⟼ 2 nd ⁡ y 1 st ⁡ y
2 1 elcnvlem ⊢ A ∈ ⋂ x | φ -1 ↔ A ∈ V × V ∧ y ∈ V × V ⟼ 2 nd ⁡ y 1 st ⁡ y ⁡ A ∈ ⋂ x | φ
3 1 elcnvlem ⊢ A ∈ x -1 ↔ A ∈ V × V ∧ y ∈ V × V ⟼ 2 nd ⁡ y 1 st ⁡ y ⁡ A ∈ x
4 2 3 elmapintab ⊢ A ∈ ⋂ x | φ -1 ↔ A ∈ V × V ∧ ∀ x φ → A ∈ x -1