Metamath Proof Explorer
Description: Subclass theorem for disjoint elementhood, deduction version.
(Contributed by Peter Mazsa, 28-Sep-2021)
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Ref |
Expression |
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Hypothesis |
eldisjssd.1 |
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Assertion |
eldisjssd |
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Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
eldisjssd.1 |
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2 |
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eldisjss |
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3 |
1 2
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syl |
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