Metamath Proof Explorer


Theorem eldisjssd

Description: Subclass theorem for disjoint elementhood, deduction version. (Contributed by Peter Mazsa, 28-Sep-2021)

Ref Expression
Hypothesis eldisjssd.1 ⊢ φ → A ⊆ B
Assertion eldisjssd ⊢ φ → ElDisj B → ElDisj A

Proof

Step Hyp Ref Expression
1 eldisjssd.1 ⊢ φ → A ⊆ B
2 eldisjss ⊢ A ⊆ B → ElDisj B → ElDisj A
3 1 2 syl ⊢ φ → ElDisj B → ElDisj A