Metamath Proof Explorer


Theorem elrelscnveq

Description: Two ways of saying a relation is symmetric. (Contributed by Peter Mazsa, 22-Aug-2021)

Ref Expression
Assertion elrelscnveq ⊢ R ∈ Rels → R -1 ⊆ R ↔ R -1 = R

Proof

Step Hyp Ref Expression
1 elrelscnveq3 ⊢ R ∈ Rels → R = R -1 ↔ ∀ x ∀ y x R y → y R x
2 cnvsym ⊢ R -1 ⊆ R ↔ ∀ x ∀ y x R y → y R x
3 1 2 bitr4di ⊢ R ∈ Rels → R = R -1 ↔ R -1 ⊆ R
4 eqcom ⊢ R = R -1 ↔ R -1 = R
5 3 4 bitr3di ⊢ R ∈ Rels → R -1 ⊆ R ↔ R -1 = R