Metamath Proof Explorer


Theorem elrestr

Description: Sufficient condition for being an open set in a subspace. (Contributed by Jeff Hankins, 11-Jul-2009) (Revised by Mario Carneiro, 15-Dec-2013)

Ref Expression
Assertion elrestr ⊢ J ∈ V ∧ S ∈ W ∧ A ∈ J → A ∩ S ∈ J ↾ 𝑡 S

Proof

Step Hyp Ref Expression
1 eqid ⊢ A ∩ S = A ∩ S
2 ineq1 ⊢ x = A → x ∩ S = A ∩ S
3 2 rspceeqv ⊢ A ∈ J ∧ A ∩ S = A ∩ S → ∃ x ∈ J A ∩ S = x ∩ S
4 1 3 mpan2 ⊢ A ∈ J → ∃ x ∈ J A ∩ S = x ∩ S
5 elrest ⊢ J ∈ V ∧ S ∈ W → A ∩ S ∈ J ↾ 𝑡 S ↔ ∃ x ∈ J A ∩ S = x ∩ S
6 4 5 imbitrrid ⊢ J ∈ V ∧ S ∈ W → A ∈ J → A ∩ S ∈ J ↾ 𝑡 S
7 6 3impia ⊢ J ∈ V ∧ S ∈ W ∧ A ∈ J → A ∩ S ∈ J ↾ 𝑡 S