Metamath Proof Explorer


Theorem eqabri

Description: Equality of a class variable and a class abstraction (inference form). (Contributed by NM, 3-Apr-1996) (Proof shortened by Wolf Lammen, 15-Nov-2019)

Ref Expression
Hypothesis eqabri.1 ⊢ A = x | φ
Assertion eqabri ⊢ x ∈ A ↔ φ

Proof

Step Hyp Ref Expression
1 eqabri.1 ⊢ A = x | φ
2 1 a1i ⊢ ⊤ → A = x | φ
3 2 eqabrd ⊢ ⊤ → x ∈ A ↔ φ
4 3 mptru ⊢ x ∈ A ↔ φ