Theorem eqimsscd

Description: Equality implies inclusion, deduction version. (Contributed by SN, 15-Feb-2025)

	Ref	Expression
Hypothesis	eqimssd.1	$$⊢\phi \to A=B$$
Assertion	eqimsscd	$$⊢\phi \to B\subseteq A$$

Proof

Step	Hyp	Ref	Expression
1		eqimssd.1	$$⊢\phi \to A=B$$
2		ssid	$$⊢A\subseteq A$$
3	1 2	eqsstrrdi	$$⊢\phi \to B\subseteq A$$