Theorem eqimssd

Description: Equality implies inclusion, deduction version. (Contributed by SN, 6-Nov-2024)

	Ref	Expression
Hypothesis	eqimssd.1	$$⊢\phi \to A=B$$
Assertion	eqimssd	$$⊢\phi \to A\subseteq B$$

Proof

Step	Hyp	Ref	Expression
1		eqimssd.1	$$⊢\phi \to A=B$$
2		ssid	$$⊢B\subseteq B$$
3	1 2	eqsstrdi	$$⊢\phi \to A\subseteq B$$