Metamath Proof Explorer


Theorem equcomd

Description: Deduction form of equcom , symmetry of equality. For the versions for classes, see eqcom and eqcomd . (Contributed by BJ, 6-Oct-2019)

Ref Expression
Hypothesis equcomd.1 φx=y
Assertion equcomd φy=x

Proof

Step Hyp Ref Expression
1 equcomd.1 φx=y
2 equcom x=yy=x
3 1 2 sylib φy=x