Metamath Proof Explorer


Theorem equcomd

Description: Deduction form of equcom , symmetry of equality. For the versions for classes, see eqcom and eqcomd . (Contributed by BJ, 6-Oct-2019)

Ref Expression
Hypothesis equcomd.1 φ x = y
Assertion equcomd φ y = x

Proof

Step Hyp Ref Expression
1 equcomd.1 φ x = y
2 equcom x = y y = x
3 1 2 sylib φ y = x