Metamath Proof Explorer


Theorem equsalhw

Description: Version of equsalh with a disjoint variable condition, which does not require ax-13 . (Contributed by NM, 29-Nov-2015) (Proof shortened by Wolf Lammen, 8-Jul-2022)

Ref Expression
Hypotheses equsalhw.1 ψxψ
equsalhw.2 x=yφψ
Assertion equsalhw xx=yφψ

Proof

Step Hyp Ref Expression
1 equsalhw.1 ψxψ
2 equsalhw.2 x=yφψ
3 1 nf5i xψ
4 3 2 equsalv xx=yφψ