Metamath Proof Explorer


Theorem equsexhv

Description: An equivalence related to implicit substitution. Version of equsexh with a disjoint variable condition, which does not require ax-13 . (Contributed by NM, 5-Aug-1993) (Revised by BJ, 31-May-2019)

Ref Expression
Hypotheses equsalhw.1 ⊢ ψ → ∀ x ψ
equsalhw.2 ⊢ x = y → φ ↔ ψ
Assertion equsexhv ⊢ ∃ x x = y ∧ φ ↔ ψ

Proof

Step Hyp Ref Expression
1 equsalhw.1 ⊢ ψ → ∀ x ψ
2 equsalhw.2 ⊢ x = y → φ ↔ ψ
3 1 nf5i ⊢ Ⅎ x ψ
4 3 2 equsexv ⊢ ∃ x x = y ∧ φ ↔ ψ