Metamath Proof Explorer


Theorem ercl2

Description: Elementhood in the field of an equivalence relation. (Contributed by Mario Carneiro, 12-Aug-2015)

Ref Expression
Hypotheses ersym.1 φRErX
ersym.2 φARB
Assertion ercl2 φBX

Proof

Step Hyp Ref Expression
1 ersym.1 φRErX
2 ersym.2 φARB
3 1 2 ersym φBRA
4 1 3 ercl φBX