Metamath Proof Explorer


Theorem ersym

Description: An equivalence relation is symmetric. (Contributed by NM, 4-Jun-1995) (Revised by Mario Carneiro, 12-Aug-2015)

Ref Expression
Hypotheses ersym.1 φRErX
ersym.2 φARB
Assertion ersym φBRA

Proof

Step Hyp Ref Expression
1 ersym.1 φRErX
2 ersym.2 φARB
3 errel RErXRelR
4 1 3 syl φRelR
5 brrelex12 RelRARBAVBV
6 4 2 5 syl2anc φAVBV
7 brcnvg BVAVBR-1AARB
8 7 ancoms AVBVBR-1AARB
9 6 8 syl φBR-1AARB
10 2 9 mpbird φBR-1A
11 df-er RErXRelRdomR=XR-1RRR
12 11 simp3bi RErXR-1RRR
13 1 12 syl φR-1RRR
14 13 unssad φR-1R
15 14 ssbrd φBR-1ABRA
16 10 15 mpd φBRA