Metamath Proof Explorer


Theorem f1cdmsn

Description: If a one-to-one function with a nonempty domain has a singleton as its codomain, its domain must also be a singleton. (Contributed by BTernaryTau, 1-Dec-2024)

Ref Expression
Assertion f1cdmsn ⊢ F : A ⟶ 1-1 B ∧ A ≠ ∅ → ∃ x A = x

Proof

Step Hyp Ref Expression
1 f1f ⊢ F : A ⟶ 1-1 B → F : A ⟶ B
2 fvconst ⊢ F : A ⟶ B ∧ y ∈ A → F ⁡ y = B
3 2 3adant3 ⊢ F : A ⟶ B ∧ y ∈ A ∧ z ∈ A → F ⁡ y = B
4 fvconst ⊢ F : A ⟶ B ∧ z ∈ A → F ⁡ z = B
5 4 3adant2 ⊢ F : A ⟶ B ∧ y ∈ A ∧ z ∈ A → F ⁡ z = B
6 3 5 eqtr4d ⊢ F : A ⟶ B ∧ y ∈ A ∧ z ∈ A → F ⁡ y = F ⁡ z
7 1 6 syl3an1 ⊢ F : A ⟶ 1-1 B ∧ y ∈ A ∧ z ∈ A → F ⁡ y = F ⁡ z
8 f1veqaeq ⊢ F : A ⟶ 1-1 B ∧ y ∈ A ∧ z ∈ A → F ⁡ y = F ⁡ z → y = z
9 8 3impb ⊢ F : A ⟶ 1-1 B ∧ y ∈ A ∧ z ∈ A → F ⁡ y = F ⁡ z → y = z
10 7 9 mpd ⊢ F : A ⟶ 1-1 B ∧ y ∈ A ∧ z ∈ A → y = z
11 10 3expia ⊢ F : A ⟶ 1-1 B ∧ y ∈ A → z ∈ A → y = z
12 11 ralrimiv ⊢ F : A ⟶ 1-1 B ∧ y ∈ A → ∀ z ∈ A y = z
13 12 reximdva0 ⊢ F : A ⟶ 1-1 B ∧ A ≠ ∅ → ∃ y ∈ A ∀ z ∈ A y = z
14 issn ⊢ ∃ y ∈ A ∀ z ∈ A y = z → ∃ x A = x
15 13 14 syl ⊢ F : A ⟶ 1-1 B ∧ A ≠ ∅ → ∃ x A = x