Metamath Proof Explorer


Theorem fdmd

Description: Deduction form of fdm . The domain of a mapping. (Contributed by Glauco Siliprandi, 26-Jun-2021)

Ref Expression
Hypothesis fdmd.1 φF:AB
Assertion fdmd φdomF=A

Proof

Step Hyp Ref Expression
1 fdmd.1 φF:AB
2 fdm F:ABdomF=A
3 1 2 syl φdomF=A