Metamath Proof Explorer


Theorem fdmd

Description: Deduction form of fdm . The domain of a mapping. (Contributed by Glauco Siliprandi, 26-Jun-2021)

Ref Expression
Hypothesis fdmd.1 ⊢ φ → F : A ⟶ B
Assertion fdmd ⊢ φ → dom ⁡ F = A

Proof

Step Hyp Ref Expression
1 fdmd.1 ⊢ φ → F : A ⟶ B
2 fdm ⊢ F : A ⟶ B → dom ⁡ F = A
3 1 2 syl ⊢ φ → dom ⁡ F = A