Metamath Proof Explorer


Theorem filinn0

Description: The intersection of two elements of a filter can't be empty. (Contributed by FL, 16-Sep-2007) (Revised by Stefan O'Rear, 28-Jul-2015)

Ref Expression
Assertion filinn0 ⊢ F ∈ Fil ⁡ X ∧ A ∈ F ∧ B ∈ F → A ∩ B ≠ ∅

Proof

Step Hyp Ref Expression
1 simp1 ⊢ F ∈ Fil ⁡ X ∧ A ∈ F ∧ B ∈ F → F ∈ Fil ⁡ X
2 filin ⊢ F ∈ Fil ⁡ X ∧ A ∈ F ∧ B ∈ F → A ∩ B ∈ F
3 fileln0 ⊢ F ∈ Fil ⁡ X ∧ A ∩ B ∈ F → A ∩ B ≠ ∅
4 1 2 3 syl2anc ⊢ F ∈ Fil ⁡ X ∧ A ∈ F ∧ B ∈ F → A ∩ B ≠ ∅