Metamath Proof Explorer


Theorem filintn0

Description: A filter has the finite intersection property. Remark below Definition 1 of BourbakiTop1 p. I.36. (Contributed by FL, 20-Sep-2007) (Revised by Stefan O'Rear, 28-Jul-2015)

Ref Expression
Assertion filintn0 ⊢ F ∈ Fil ⁡ X ∧ A ⊆ F ∧ A ≠ ∅ ∧ A ∈ Fin → ⋂ A ≠ ∅

Proof

Step Hyp Ref Expression
1 elfir ⊢ F ∈ Fil ⁡ X ∧ A ⊆ F ∧ A ≠ ∅ ∧ A ∈ Fin → ⋂ A ∈ fi ⁡ F
2 filfi ⊢ F ∈ Fil ⁡ X → fi ⁡ F = F
3 2 adantr ⊢ F ∈ Fil ⁡ X ∧ A ⊆ F ∧ A ≠ ∅ ∧ A ∈ Fin → fi ⁡ F = F
4 1 3 eleqtrd ⊢ F ∈ Fil ⁡ X ∧ A ⊆ F ∧ A ≠ ∅ ∧ A ∈ Fin → ⋂ A ∈ F
5 fileln0 ⊢ F ∈ Fil ⁡ X ∧ ⋂ A ∈ F → ⋂ A ≠ ∅
6 4 5 syldan ⊢ F ∈ Fil ⁡ X ∧ A ⊆ F ∧ A ≠ ∅ ∧ A ∈ Fin → ⋂ A ≠ ∅