Metamath Proof Explorer


Theorem fndmexb

Description: The domain of a function is a set iff the function is a set. (Contributed by AV, 8-Aug-2024)

Ref Expression
Assertion fndmexb ⊢ F Fn A → A ∈ V ↔ F ∈ V

Proof

Step Hyp Ref Expression
1 fnex ⊢ F Fn A ∧ A ∈ V → F ∈ V
2 1 ex ⊢ F Fn A → A ∈ V → F ∈ V
3 simpr ⊢ F Fn A ∧ F ∈ V → F ∈ V
4 simpl ⊢ F Fn A ∧ F ∈ V → F Fn A
5 3 4 fndmexd ⊢ F Fn A ∧ F ∈ V → A ∈ V
6 5 ex ⊢ F Fn A → F ∈ V → A ∈ V
7 2 6 impbid ⊢ F Fn A → A ∈ V ↔ F ∈ V