Metamath Proof Explorer


Theorem fndmexd

Description: If a function is a set, its domain is a set. (Contributed by Rohan Ridenour, 13-May-2024)

Ref Expression
Hypotheses fndmexd.1 ⊢ φ → F ∈ V
fndmexd.2 ⊢ φ → F Fn D
Assertion fndmexd ⊢ φ → D ∈ V

Proof

Step Hyp Ref Expression
1 fndmexd.1 ⊢ φ → F ∈ V
2 fndmexd.2 ⊢ φ → F Fn D
3 2 fndmd ⊢ φ → dom ⁡ F = D
4 1 dmexd ⊢ φ → dom ⁡ F ∈ V
5 3 4 eqeltrrd ⊢ φ → D ∈ V