Metamath Proof Explorer
		
		
		
		Description:  If a function is a set, its domain is a set.  (Contributed by Rohan
       Ridenour, 13-May-2024)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | fndmexd.1 | ⊢ ( 𝜑  →  𝐹  ∈  𝑉 ) | 
					
						|  |  | fndmexd.2 | ⊢ ( 𝜑  →  𝐹  Fn  𝐷 ) | 
				
					|  | Assertion | fndmexd | ⊢  ( 𝜑  →  𝐷  ∈  V ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | fndmexd.1 | ⊢ ( 𝜑  →  𝐹  ∈  𝑉 ) | 
						
							| 2 |  | fndmexd.2 | ⊢ ( 𝜑  →  𝐹  Fn  𝐷 ) | 
						
							| 3 | 2 | fndmd | ⊢ ( 𝜑  →  dom  𝐹  =  𝐷 ) | 
						
							| 4 | 1 | dmexd | ⊢ ( 𝜑  →  dom  𝐹  ∈  V ) | 
						
							| 5 | 3 4 | eqeltrrd | ⊢ ( 𝜑  →  𝐷  ∈  V ) |