Metamath Proof Explorer


Theorem fndmu

Description: A function has a unique domain. (Contributed by NM, 11-Aug-1994)

Ref Expression
Assertion fndmu ⊢ F Fn A ∧ F Fn B → A = B

Proof

Step Hyp Ref Expression
1 fndm ⊢ F Fn A → dom ⁡ F = A
2 fndm ⊢ F Fn B → dom ⁡ F = B
3 1 2 sylan9req ⊢ F Fn A ∧ F Fn B → A = B