Metamath Proof Explorer


Theorem fr0

Description: Any relation is well-founded on the empty set. (Contributed by NM, 17-Sep-1993)

Ref Expression
Assertion fr0 ⊢ R Fr ∅

Proof

Step Hyp Ref Expression
1 dffr2 ⊢ R Fr ∅ ↔ ∀ x x ⊆ ∅ ∧ x ≠ ∅ → ∃ y ∈ x z ∈ x | z R y = ∅
2 ss0 ⊢ x ⊆ ∅ → x = ∅
3 2 a1d ⊢ x ⊆ ∅ → ¬ ∃ y ∈ x z ∈ x | z R y = ∅ → x = ∅
4 3 necon1ad ⊢ x ⊆ ∅ → x ≠ ∅ → ∃ y ∈ x z ∈ x | z R y = ∅
5 4 imp ⊢ x ⊆ ∅ ∧ x ≠ ∅ → ∃ y ∈ x z ∈ x | z R y = ∅
6 1 5 mpgbir ⊢ R Fr ∅