Metamath Proof Explorer


Theorem fuco112xa

Description: The object part of the functor composition bifunctor maps two functors to their composition, expressed explicitly for the morphism part of the composed functor. A morphism is mapped by two functors in succession. (Contributed by Zhi Wang, 3-Oct-2025)

Ref Expression
Hypotheses fuco11.o No typesetting found for |- ( ph -> ( <. C , D >. o.F E ) = <. O , P >. ) with typecode |-
fuco11.f ⊢ φ → F C Func D G
fuco11.k ⊢ φ → K D Func E L
fuco11.u ⊢ φ → U = K L F G
fuco111x.x ⊢ φ → X ∈ Base C
fuco112x.y ⊢ φ → Y ∈ Base C
fuco112xa.a ⊢ φ → A ∈ X Hom ⁡ C Y
Assertion fuco112xa ⊢ φ → X 2 nd ⁡ O ⁡ U Y ⁡ A = F ⁡ X L F ⁡ Y ⁡ X G Y ⁡ A

Proof

Step Hyp Ref Expression
1 fuco11.o Could not format ( ph -> ( <. C , D >. o.F E ) = <. O , P >. ) : No typesetting found for |- ( ph -> ( <. C , D >. o.F E ) = <. O , P >. ) with typecode |-
2 fuco11.f ⊢ φ → F C Func D G
3 fuco11.k ⊢ φ → K D Func E L
4 fuco11.u ⊢ φ → U = K L F G
5 fuco111x.x ⊢ φ → X ∈ Base C
6 fuco112x.y ⊢ φ → Y ∈ Base C
7 fuco112xa.a ⊢ φ → A ∈ X Hom ⁡ C Y
8 1 2 3 4 5 6 fuco112x ⊢ φ → X 2 nd ⁡ O ⁡ U Y = F ⁡ X L F ⁡ Y ∘ X G Y
9 8 fveq1d ⊢ φ → X 2 nd ⁡ O ⁡ U Y ⁡ A = F ⁡ X L F ⁡ Y ∘ X G Y ⁡ A
10 eqid ⊢ Base C = Base C
11 eqid ⊢ Hom ⁡ C = Hom ⁡ C
12 eqid ⊢ Hom ⁡ D = Hom ⁡ D
13 10 11 12 2 5 6 funcf2 ⊢ φ → X G Y : X Hom ⁡ C Y ⟶ F ⁡ X Hom ⁡ D F ⁡ Y
14 13 7 fvco3d ⊢ φ → F ⁡ X L F ⁡ Y ∘ X G Y ⁡ A = F ⁡ X L F ⁡ Y ⁡ X G Y ⁡ A
15 9 14 eqtrd ⊢ φ → X 2 nd ⁡ O ⁡ U Y ⁡ A = F ⁡ X L F ⁡ Y ⁡ X G Y ⁡ A