Metamath Proof Explorer


Theorem fundcmpsurinjlem1

Description: Lemma 1 for fundcmpsurinj . (Contributed by AV, 4-Mar-2024)

Ref Expression
Hypotheses fundcmpsurinj.p P = z | x A z = F -1 F x
fundcmpsurinj.g G = x A F -1 F x
Assertion fundcmpsurinjlem1 ran G = P

Proof

Step Hyp Ref Expression
1 fundcmpsurinj.p P = z | x A z = F -1 F x
2 fundcmpsurinj.g G = x A F -1 F x
3 2 rnmpt ran G = z | x A z = F -1 F x
4 3 1 eqtr4i ran G = P