Metamath Proof Explorer


Theorem funeq

Description: Equality theorem for function predicate. (Contributed by NM, 16-Aug-1994)

Ref Expression
Assertion funeq A=BFunAFunB

Proof

Step Hyp Ref Expression
1 eqimss2 A=BBA
2 funss BAFunAFunB
3 1 2 syl A=BFunAFunB
4 eqimss A=BAB
5 funss ABFunBFunA
6 4 5 syl A=BFunBFunA
7 3 6 impbid A=BFunAFunB