Metamath Proof Explorer


Theorem fvfundmfvn0

Description: If the "value of a class" at an argument is not the empty set, then the argument is in the domain of the class and the class restricted to the singleton formed on that argument is a function. (Contributed by Alexander van der Vekens, 26-May-2017) (Proof shortened by BJ, 13-Aug-2022)

Ref Expression
Assertion fvfundmfvn0 ⊢ F ⁡ A ≠ ∅ → A ∈ dom ⁡ F ∧ Fun ⁡ F ↾ A

Proof

Step Hyp Ref Expression
1 ndmfv ⊢ ¬ A ∈ dom ⁡ F → F ⁡ A = ∅
2 1 necon1ai ⊢ F ⁡ A ≠ ∅ → A ∈ dom ⁡ F
3 nfunsn ⊢ ¬ Fun ⁡ F ↾ A → F ⁡ A = ∅
4 3 necon1ai ⊢ F ⁡ A ≠ ∅ → Fun ⁡ F ↾ A
5 2 4 jca ⊢ F ⁡ A ≠ ∅ → A ∈ dom ⁡ F ∧ Fun ⁡ F ↾ A