Metamath Proof Explorer


Theorem fvmptd

Description: Deduction version of fvmpt . (Contributed by Scott Fenton, 18-Feb-2013) (Revised by Mario Carneiro, 31-Aug-2015) (Proof shortened by AV, 29-Mar-2024)

Ref Expression
Hypotheses fvmptd.1 ⊢ φ → F = x ∈ D ⟼ B
fvmptd.2 ⊢ φ ∧ x = A → B = C
fvmptd.3 ⊢ φ → A ∈ D
fvmptd.4 ⊢ φ → C ∈ V
Assertion fvmptd ⊢ φ → F ⁡ A = C

Proof

Step Hyp Ref Expression
1 fvmptd.1 ⊢ φ → F = x ∈ D ⟼ B
2 fvmptd.2 ⊢ φ ∧ x = A → B = C
3 fvmptd.3 ⊢ φ → A ∈ D
4 fvmptd.4 ⊢ φ → C ∈ V
5 nfv ⊢ Ⅎ x φ
6 nfcv ⊢ Ⅎ _ x A
7 nfcv ⊢ Ⅎ _ x C
8 1 2 3 4 5 6 7 fvmptdf ⊢ φ → F ⁡ A = C