Metamath Proof Explorer


Theorem ghmpropd

Description: Group homomorphism depends only on the group attributes of structures. (Contributed by Mario Carneiro, 12-Jun-2015)

Ref Expression
Hypotheses ghmpropd.a ⊢ φ → B = Base J
ghmpropd.b ⊢ φ → C = Base K
ghmpropd.c ⊢ φ → B = Base L
ghmpropd.d ⊢ φ → C = Base M
ghmpropd.e ⊢ φ ∧ x ∈ B ∧ y ∈ B → x + J y = x + L y
ghmpropd.f ⊢ φ ∧ x ∈ C ∧ y ∈ C → x + K y = x + M y
Assertion ghmpropd ⊢ φ → J GrpHom K = L GrpHom M

Proof

Step Hyp Ref Expression
1 ghmpropd.a ⊢ φ → B = Base J
2 ghmpropd.b ⊢ φ → C = Base K
3 ghmpropd.c ⊢ φ → B = Base L
4 ghmpropd.d ⊢ φ → C = Base M
5 ghmpropd.e ⊢ φ ∧ x ∈ B ∧ y ∈ B → x + J y = x + L y
6 ghmpropd.f ⊢ φ ∧ x ∈ C ∧ y ∈ C → x + K y = x + M y
7 1 3 5 grppropd ⊢ φ → J ∈ Grp ↔ L ∈ Grp
8 2 4 6 grppropd ⊢ φ → K ∈ Grp ↔ M ∈ Grp
9 7 8 anbi12d ⊢ φ → J ∈ Grp ∧ K ∈ Grp ↔ L ∈ Grp ∧ M ∈ Grp
10 1 2 3 4 5 6 mhmpropd ⊢ φ → J MndHom K = L MndHom M
11 10 eleq2d ⊢ φ → f ∈ J MndHom K ↔ f ∈ L MndHom M
12 9 11 anbi12d ⊢ φ → J ∈ Grp ∧ K ∈ Grp ∧ f ∈ J MndHom K ↔ L ∈ Grp ∧ M ∈ Grp ∧ f ∈ L MndHom M
13 ghmgrp1 ⊢ f ∈ J GrpHom K → J ∈ Grp
14 ghmgrp2 ⊢ f ∈ J GrpHom K → K ∈ Grp
15 13 14 jca ⊢ f ∈ J GrpHom K → J ∈ Grp ∧ K ∈ Grp
16 ghmmhmb ⊢ J ∈ Grp ∧ K ∈ Grp → J GrpHom K = J MndHom K
17 16 eleq2d ⊢ J ∈ Grp ∧ K ∈ Grp → f ∈ J GrpHom K ↔ f ∈ J MndHom K
18 15 17 biadanii ⊢ f ∈ J GrpHom K ↔ J ∈ Grp ∧ K ∈ Grp ∧ f ∈ J MndHom K
19 ghmgrp1 ⊢ f ∈ L GrpHom M → L ∈ Grp
20 ghmgrp2 ⊢ f ∈ L GrpHom M → M ∈ Grp
21 19 20 jca ⊢ f ∈ L GrpHom M → L ∈ Grp ∧ M ∈ Grp
22 ghmmhmb ⊢ L ∈ Grp ∧ M ∈ Grp → L GrpHom M = L MndHom M
23 22 eleq2d ⊢ L ∈ Grp ∧ M ∈ Grp → f ∈ L GrpHom M ↔ f ∈ L MndHom M
24 21 23 biadanii ⊢ f ∈ L GrpHom M ↔ L ∈ Grp ∧ M ∈ Grp ∧ f ∈ L MndHom M
25 12 18 24 3bitr4g ⊢ φ → f ∈ J GrpHom K ↔ f ∈ L GrpHom M
26 25 eqrdv ⊢ φ → J GrpHom K = L GrpHom M