Metamath Proof Explorer


Theorem grplactf1o

Description: The left group action of element A of group G maps the underlying set X of G one-to-one onto itself. (Contributed by Paul Chapman, 18-Mar-2008) (Proof shortened by Mario Carneiro, 14-Aug-2015)

Ref Expression
Hypotheses grplact.1 ⊢ F = g ∈ X ⟼ a ∈ X ⟼ g + ˙ a
grplact.2 ⊢ X = Base G
grplact.3 ⊢ + ˙ = + G
Assertion grplactf1o ⊢ G ∈ Grp ∧ A ∈ X → F ⁡ A : X ⟶ 1-1 onto X

Proof

Step Hyp Ref Expression
1 grplact.1 ⊢ F = g ∈ X ⟼ a ∈ X ⟼ g + ˙ a
2 grplact.2 ⊢ X = Base G
3 grplact.3 ⊢ + ˙ = + G
4 eqid ⊢ inv g ⁡ G = inv g ⁡ G
5 1 2 3 4 grplactcnv ⊢ G ∈ Grp ∧ A ∈ X → F ⁡ A : X ⟶ 1-1 onto X ∧ F ⁡ A -1 = F ⁡ inv g ⁡ G ⁡ A
6 5 simpld ⊢ G ∈ Grp ∧ A ∈ X → F ⁡ A : X ⟶ 1-1 onto X