Metamath Proof Explorer


Theorem h1dn0

Description: A nonzero vector generates a (nonzero) 1-dimensional subspace. (Contributed by NM, 22-Jul-2001) (New usage is discouraged.)

Ref Expression
Assertion h1dn0 ⊢ A ∈ ℋ ∧ A ≠ 0 ℎ → ⊥ ⁡ ⊥ ⁡ A ≠ 0 ℋ

Proof

Step Hyp Ref Expression
1 h1did ⊢ A ∈ ℋ → A ∈ ⊥ ⁡ ⊥ ⁡ A
2 eleq2 ⊢ ⊥ ⁡ ⊥ ⁡ A = 0 ℋ → A ∈ ⊥ ⁡ ⊥ ⁡ A ↔ A ∈ 0 ℋ
3 1 2 syl5ibcom ⊢ A ∈ ℋ → ⊥ ⁡ ⊥ ⁡ A = 0 ℋ → A ∈ 0 ℋ
4 elch0 ⊢ A ∈ 0 ℋ ↔ A = 0 ℎ
5 3 4 imbitrdi ⊢ A ∈ ℋ → ⊥ ⁡ ⊥ ⁡ A = 0 ℋ → A = 0 ℎ
6 5 necon3d ⊢ A ∈ ℋ → A ≠ 0 ℎ → ⊥ ⁡ ⊥ ⁡ A ≠ 0 ℋ
7 6 imp ⊢ A ∈ ℋ ∧ A ≠ 0 ℎ → ⊥ ⁡ ⊥ ⁡ A ≠ 0 ℋ