Metamath Proof Explorer


Theorem hashnnsuc

Description: The # function on _om turns successor into adding 1. (Contributed by Eric Schmidt, 7-Jul-2026)

Ref Expression
Assertion hashnnsuc ⊢ A ∈ ω → suc ⁡ A = A + 1

Proof

Step Hyp Ref Expression
1 nnon ⊢ A ∈ ω → A ∈ On
2 oa1suc ⊢ A ∈ On → A + 𝑜 1 𝑜 = suc ⁡ A
3 1 2 syl ⊢ A ∈ ω → A + 𝑜 1 𝑜 = suc ⁡ A
4 3 fveq2d ⊢ A ∈ ω → A + 𝑜 1 𝑜 = suc ⁡ A
5 1onn ⊢ 1 𝑜 ∈ ω
6 hashnna ⊢ A ∈ ω ∧ 1 𝑜 ∈ ω → A + 𝑜 1 𝑜 = A + 1 𝑜
7 5 6 mpan2 ⊢ A ∈ ω → A + 𝑜 1 𝑜 = A + 1 𝑜
8 4 7 eqtr3d ⊢ A ∈ ω → suc ⁡ A = A + 1 𝑜
9 hash1 ⊢ 1 𝑜 = 1
10 9 oveq2i ⊢ A + 1 𝑜 = A + 1
11 8 10 eqtrdi ⊢ A ∈ ω → suc ⁡ A = A + 1