Metamath Proof Explorer


Theorem hashnnsuc

Description: The # function on _om turns successor into adding 1. (Contributed by Eric Schmidt, 7-Jul-2026)

Ref Expression
Assertion hashnnsuc A ω suc A = A + 1

Proof

Step Hyp Ref Expression
1 nnon A ω A On
2 oa1suc A On A + 𝑜 1 𝑜 = suc A
3 1 2 syl A ω A + 𝑜 1 𝑜 = suc A
4 3 fveq2d A ω A + 𝑜 1 𝑜 = suc A
5 1onn 1 𝑜 ω
6 hashnna A ω 1 𝑜 ω A + 𝑜 1 𝑜 = A + 1 𝑜
7 5 6 mpan2 A ω A + 𝑜 1 𝑜 = A + 1 𝑜
8 4 7 eqtr3d A ω suc A = A + 1 𝑜
9 hash1 1 𝑜 = 1
10 9 oveq2i A + 1 𝑜 = A + 1
11 8 10 eqtrdi A ω suc A = A + 1