Metamath Proof Explorer


Theorem oa1suc

Description: Addition with 1 is same as successor. Proposition 4.34(a) of Mendelson p. 266. (Contributed by NM, 29-Oct-1995) (Revised by Mario Carneiro, 16-Nov-2014)

Ref Expression
Assertion oa1suc AOnA+𝑜1𝑜=sucA

Proof

Step Hyp Ref Expression
1 df-1o 1𝑜=suc
2 1 oveq2i A+𝑜1𝑜=A+𝑜suc
3 peano1 ω
4 onasuc AOnωA+𝑜suc=sucA+𝑜
5 3 4 mpan2 AOnA+𝑜suc=sucA+𝑜
6 2 5 eqtrid AOnA+𝑜1𝑜=sucA+𝑜
7 oa0 AOnA+𝑜=A
8 suceq A+𝑜=AsucA+𝑜=sucA
9 7 8 syl AOnsucA+𝑜=sucA
10 6 9 eqtrd AOnA+𝑜1𝑜=sucA