Metamath Proof Explorer


Theorem oa1suc

Description: Addition with 1 is same as successor. Proposition 4.34(a) of Mendelson p. 266. Remark 2.4 of Schloeder p. 4. (Contributed by NM, 29-Oct-1995) (Revised by Mario Carneiro, 16-Nov-2014)

Ref Expression
Assertion oa1suc ⊢ A ∈ On → A + 𝑜 1 𝑜 = suc ⁡ A

Proof

Step Hyp Ref Expression
1 df-1o ⊢ 1 𝑜 = suc ⁡ ∅
2 1 oveq2i ⊢ A + 𝑜 1 𝑜 = A + 𝑜 suc ⁡ ∅
3 peano1 ⊢ ∅ ∈ ω
4 onasuc ⊢ A ∈ On ∧ ∅ ∈ ω → A + 𝑜 suc ⁡ ∅ = suc ⁡ A + 𝑜 ∅
5 3 4 mpan2 ⊢ A ∈ On → A + 𝑜 suc ⁡ ∅ = suc ⁡ A + 𝑜 ∅
6 2 5 eqtrid ⊢ A ∈ On → A + 𝑜 1 𝑜 = suc ⁡ A + 𝑜 ∅
7 oa0 ⊢ A ∈ On → A + 𝑜 ∅ = A
8 suceq ⊢ A + 𝑜 ∅ = A → suc ⁡ A + 𝑜 ∅ = suc ⁡ A
9 7 8 syl ⊢ A ∈ On → suc ⁡ A + 𝑜 ∅ = suc ⁡ A
10 6 9 eqtrd ⊢ A ∈ On → A + 𝑜 1 𝑜 = suc ⁡ A