Metamath Proof Explorer


Theorem heeq1

Description: Equality law for relations being herditary over a class. (Contributed by RP, 27-Mar-2020)

Ref Expression
Assertion heeq1 ⊢ R = S → R hereditary A ↔ S hereditary A

Proof

Step Hyp Ref Expression
1 eqid ⊢ A = A
2 heeq12 ⊢ R = S ∧ A = A → R hereditary A ↔ S hereditary A
3 1 2 mpan2 ⊢ R = S → R hereditary A ↔ S hereditary A