Metamath Proof Explorer
Description: Equality law for relations being herditary over a class. (Contributed by RP, 27-Mar-2020)
|
|
Ref |
Expression |
|
Assertion |
heeq1 |
⊢ ( 𝑅 = 𝑆 → ( 𝑅 hereditary 𝐴 ↔ 𝑆 hereditary 𝐴 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
eqid |
⊢ 𝐴 = 𝐴 |
2 |
|
heeq12 |
⊢ ( ( 𝑅 = 𝑆 ∧ 𝐴 = 𝐴 ) → ( 𝑅 hereditary 𝐴 ↔ 𝑆 hereditary 𝐴 ) ) |
3 |
1 2
|
mpan2 |
⊢ ( 𝑅 = 𝑆 → ( 𝑅 hereditary 𝐴 ↔ 𝑆 hereditary 𝐴 ) ) |