Metamath Proof Explorer


Theorem heeq1

Description: Equality law for relations being herditary over a class. (Contributed by RP, 27-Mar-2020)

Ref Expression
Assertion heeq1 ( 𝑅 = 𝑆 → ( 𝑅 hereditary 𝐴 ↔ 𝑆 hereditary 𝐴 ) )

Proof

Step Hyp Ref Expression
1 eqid ⊢ 𝐴 = 𝐴
2 heeq12 ⊢ ( ( 𝑅 = 𝑆 ∧ 𝐴 = 𝐴 ) → ( 𝑅 hereditary 𝐴 ↔ 𝑆 hereditary 𝐴 ) )
3 1 2 mpan2 ⊢ ( 𝑅 = 𝑆 → ( 𝑅 hereditary 𝐴 ↔ 𝑆 hereditary 𝐴 ) )